x-2-x^2/x=y/x

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Solution for x-2-x^2/x=y/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-((x^2)/x)-2 = y/x // - y/x

x-((x^2)/x)-(y/x)-2 = 0

x-x-(y/x)-2 = 0

x^-1*(-y) = 2 // : -y

x^-1 = -2*y^-1

-1 < 0

1/(x^1) = -2*y^-1 // * x^1

1 = -2*x^1*y^-1 // : -2*y^-1

1/(-2*y^-1) = x^1

x = 1/(-2*y^-1)

x = 1/(-2*y^-1)

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